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Basic Question 3 of 10
We want to test the claim that a steady diet of wolfsbane will cause an 18-year-old werewolf to lose EXACTLY 10 lbs. over 5 months. A random sample of 49 werewolf was taken, yielding an average weight loss over 5 months of 12.5 lbs with S = 7 lbs. Let alpha = .02. What is the calculated value suitable for testing the above hypothesis?
B. 7 x 2.5
C. 2.5
A. 12.5
B. 7 x 2.5
C. 2.5
User Contributed Comments 9
| User | Comment |
|---|---|
| isida | test statistic question: (sample statistic - null value) / standard error standard error = standard deviation / sqrt N |
| Masterkang | Obviously, he read to many Harry Potter Books... |
| achu | we know it's t-test because S sample sd, not population std dev. |
| steved333 | Yes, but sample size is large, so it doesn't matter. T-stat is the same as Z in this case. |
| poomie83 | Was alpha there as useless information? |
| ybavly | @poomie83 yes |
| johntan1979 | Agree with steved333. n>30, so Z. |
| sgossett86 | the equation for variance is single bernoulli variable |
| Shaan23 | You guys need to read the notes. One we dont know if this is normal or not. Population variance is unknown. Whenever population variance is unknown always jump to t-test. But remember t-test approaches the z test when n becomes big. |
I am using your study notes and I know of at least 5 other friends of mine who used it and passed the exam last Dec. Keep up your great work!
Barnes
Learning Outcome Statements
explain hypothesis testing and its components, including statistical significance, Type I and Type II errors, and the power of a test
CFA® 2025 Level I Curriculum, Volume 1, Module 8.