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Basic Question 9 of 13
The new products officer for the Strong-n-Safe Bank is trying to determine the stated rate for a new 4 year CD. The effective rate will be 6.95% and the CD will offer continuous compounding. The advertised stated rate would be closest to ______.
B. 6.82%
C. 7.20%
A. 6.72%
B. 6.82%
C. 7.20%
User Contributed Comments 35
User | Comment |
---|---|
tawi | How did they get that? |
tawi | Ok I got it ! The formula for Eff. Ann. Rate is EAR= e^r -1 |
brimann | Using the interest conversion capabilities of the BAII+ I used the continuous compounding fuction on 12 which = 162,754 and plugged that in for C/Y, EFF = 6.95 then CPT NOM = 6.7191 |
KD101 | Brimann's idea is good. Here are the step by step Hit 2nd - [ICONV] See NOM - Hit Down Arrow See EFF - Hit 6.95 See C/Y - Hit 12 then 2nd[e^X] and hit ENTER Now Down Arrow Key Now when you see NOM - Hit CPT You get 6.7191 |
gruszewski | By the way KD101, C/Y can be any large number, why making it more difficult than it is with this e^X :-) |
gruszewski | the fastest way is ln(1.0695) |
Hamma | Thus is this the formula then? EAR(continuous compounding)= e^r - 1 0.0695 = e^r - 1 ln(1.0695)=r |
debby2 | stated interest rate = ln (1+EAR) |
Will1868 | debby2 is smart |
MARINGI | gruszewski. thats pretty fast |
Win1977 | Still confused on this one, could someone explain it based on using the BAII calc? Thanks. |
0is4eva | Recall that: FV(N) = PV * (1 + EAR)^N = PV * e^(r * N) r is the stated annual rate, EAR = effective annual rate. Abbreviate formula, recall that N=1, and solve for r: (1 + EAR) = e^(r) ln(1 + EAR) = ln( e^(r) ) ln(1 + EAR) = r ln(1.0695) = r r = 0.06719 = 6.72% |
Cooltallgal | What C/Y is 12? The question only mentioned 4 years compound, but didn't say its compounding monthly... |
faya | e^r-1 results in compounded return = 0.0695 To 'un-compound', take logs - ie. ln(1+r) = ln(1.0695) = 0.06719 as Ois4eva says. |
gizi | Using BA11 Plus: 2nd ICONV 2nd CLR WORK EFF = 6.95 C/Y = 365 (365 dys in yr) CPT NOM = 6.719 |
Kofo | pls: can someone say how to do this using the HP12C |
AndressaS | Here you go using HP12C: 6.95 ENTER 100 % 1 + g LN Total: 0.06719 x 100 = 6.72% |
StanleyMo | it has mentioned continuous compounding, so the formula use would be EAR = E^Rs-1 |
kamil1 | in HP (1+0.0695)ln Than just multiply by 100 to get rid of the rounding |
ravdo | When I do it exactly the way suggested by AndressaS and kamil1, my answer turns out to be 2.07. What am I doing wrong? Please take it step by step with the HP12C calc |
TammTamm | Thanks debby2, the way you explained this appears to be the easiest way to remember it. |
JKiro | note debby2 "formula" is for continous compounding |
gazelle | ravdo, If you are using the ALG Mode,try those following steps: 6.95[%] +1[ENTER] [G][LN] = 0.6719 X 100= 6.72% |
mwali | Hi Gizi: your method is straight forward. Thanx |
SANTOSHPRABHU | STATED INTEREST RATE = ln (1 + EAR) = ln (1+0.0695)= 0.0671912 X 100 = 6.72% (4 year CD is an additional information and will not effect in our calculation of Stated Int Rate) |
pokigbo | HP 12c Platinum 1 ENTER 0.0695 [+] [g][LN] 0.067191 100 [x] 6.72 |
hussein1978 | what is cd |
vatsal92 | Corporate Deposits |
deliawmx | CD means certificate of deposit. |
Yrazzaq88 | Use this in your texas instruments ICONV Effective interest = 6.95% C/Y = 48 (4 years) Nom = CPT =6.72 |
Chl4072 | 1.0695 [LN] Finally get the answer!!! |
marianne19 | see irazaaq for computation 4 years to 12 months = 48 months |
nohuchi | EAR(continuous compounding)= e^r - 1 2nd ICONV 2nd CLR WORK EFF = 6.95 C/Y = 365 (365 dys in yr) CPT NOM = 6.719 |
abs013 | There's too many different ways in the comment section. 2nd ICONV 2nd CLR WORK EFF = 6.95 C/Y = 12*4 = 48 CMPT NOM = 6.72 |
anthealing | [2nd][ICONV] [2nd][CLR WORK] [EFF]=6.95 [C/Y]=1,000,000,000 (means e) ]NOM][CPT]=6.719 |
I used your notes and passed ... highly recommended!
Lauren
Learning Outcome Statements
calculate and interpret annualized return measures and continuously compounded returns, and describe their appropriate uses
CFA® 2024 Level I Curriculum, Volume 1, Module 1.